从 Java 执行命令并等待命令完成

2022-01-23 00:00:00 command exec batch-file java execute

在我的 Java 程序中，我创建了一个执行命令以运行批处理文件的进程，如下所示:

In my Java program, I create a process that executes a command to run a batch file like this:

try {
        File tempFile = new File("C:/Users/Public/temp.cmd");
        tempFile.createNewFile();
        tempFile.deleteOnExit();


        setContents(tempFile, recipe.getText()); //Writes some user input to file
        String cmd = "cmd /c start " + tempFile.getPath();


        Process p = Runtime.getRuntime().exec(cmd);


        int exitVal = p.waitFor();

        refreshActionPerformed(evt);

    } catch (InterruptedException ex) {
        Logger.getLogger(mainFrame.class.getName()).log(Level.SEVERE, null, ex); 
    } catch (IOException ex) {
        Logger.getLogger(mainFrame.class.getName()).log(Level.SEVERE, null, ex);
    }

现在，我希望发生的是命令

Now, what I would like to have happen is that the command

refreshActionPerformed(evt);

仅在我调用的批处理文件完成执行后运行.但是现在，它会在命令提示符打开后立即运行.

runs only after the batch file I called has finished executing. But right now, it runs immediately after the Command Prompt opens.

我该如何解决这个问题?

How do I fix this?

推荐答案

我设法在别处找到了答案.要在批处理文件完成之前保持初始进程打开，您只需要/wait"

I manged to find the answer elsewhere. To keep the initial process open until the batch file finished all you need is "/wait"

Process p = Runtime.getRuntime().exec("cmd /C start /wait filepath.bat");
int exitVal = p.waitFor();

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