递归如何与 Java 8 Stream 一起工作?
我有一个这样的方法，我在 Streams 中使用递归:
I have a method like this where I'm using recursion with Streams:
private static List<Member> convertToFlatList(List<Member> memberList)
{
return memberList.stream().flatMap(i -> Stream.concat(Stream.of(i), convertToFlatList(i.getChildren()).stream())).collect(Collectors.toList());
}
假设一个 Member 类有一个子成员列表，它总是初始化为一个空列表.在这里，我正在做的是将成员的分层列表转换为平面列表.我理解那部分.我不明白的是这里的递归是如何工作的.
Lets say a Member class has a children list of members that is always initialized to an empty list. Here what I'm doing is converting the hierarchical list of members to a flat list. I understand that part. What I don't understand is how recursion works here.
在递归中，它在满足某些条件时终止.但在这里我没有给出任何有意终止的条件.那么终止部分在这里是如何工作的呢?
In recursion, it's terminated when certain conditions are met. But here I'm not giving any condition for terminating intentionally. So how does the termination part work here?
推荐答案
当 memberList 为空时，递归将结束，因为在这种情况下，一个空的 List 将是返回.
The recursion will end when memberList will be empty, since at this case an empty List will be returned.
即当 i.getChildren() 为空 List 时，递归调用 convertToFlatList(i.getChildren()) 将收到一个空 List，因此 Stream 管道不会进行另一个递归调用(因为它没有要执行 flatMap 的元素)，并且将返回一个空的 列表.
i.e. when i.getChildren() is an empty List, the recursive call convertToFlatList(i.getChildren()) will receive an empty List, so the Stream pipeline won't make another recursive call (since it has no elements to execute flatMap on), and will return an empty List.
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