提供流生成的限制条件
我正在编写一个代码来计算斐波那契数.使用此代码，我可以生成斐波那契数列的前 n 个数字.
I am writing a code to calculate Fibonacci numbers. With this code I can generate first n numbers of the Fibonacci sequence.
Stream.generate(new Supplier<Long>() {
private long n1 = 1;
private long n2 = 2;
@Override
public Long get() {
long fibonacci = n1;
long n3 = n2 + n1;
n1 = n2;
n2 = n3;
return fibonacci;
}
}).limit(50).forEach(System.out::println);
limit 方法返回 Stream，其中包含传递给此方法的元素数量.我想在斐波那契数达到某个值后停止生成 Stream.
The method limit returns the Stream which holds the number of elements passed to this method. I want to stop the generation of the Stream after the Fibonacci number reached some value.
我的意思是，如果我想列出所有小于 1000 的斐波那契数，那么我不能使用 limit，因为我不知道可能有多少个斐波那契数.
I mean if I want to list all Fibonacci numbers less than 1000 then I cannot use limit, because I don't know how many Fibonacci numbers there could be.
有没有办法使用 lambda 表达式来做到这一点?
Is there any way to do this using lambda expressions?
推荐答案
我能找到的使用 Stream 内置功能的最佳解决方案是:
The best solution using the Stream’s built-in features I could find is:
LongStream.generate(new LongSupplier() {
private long n1 = 1, n2 = 2;
public long getAsLong() {
long fibonacci = n1;
long n3 = n2 + n1;
n1 = n2;
n2 = n3;
return fibonacci;
}
}).peek(System.out::println).filter(x->x>1000).findFirst();
它的缺点是处理第一个项目是 >=1000.这可以通过使语句有条件来防止，例如
It has the disadvantage of processing the first item being >=1000 though. This can be prevented by making the statement conditional, e.g.
.peek(x->{if(x<=1000) System.out.println(x);}).filter(x->x>1000).findFirst();
但我不喜欢对相同的条件(大于或不大于千)进行两次评估.但是，对于需要基于结果值的限制的实际任务，这两种解决方案中的一种可能足够实用.
but I don’t like to evaluate the same condition (bigger than thousand or not) twice. But maybe one of these two solution might be practical enough for real life tasks where a limit based on the resulting value is needed.
我认为，很明显整个构造不具备并行能力……
I think, it’s clear that the entire construct is not parallel capable…
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