Jersey/Jackson:如何捕获 json 映射异常?

2022-01-21 00:00:00 json java jersey

我想在我的 restful 服务中捕获 json 映射异常，以防输入 json 无效.

I would like to catch json mapping exception in my restful service in case input json is not valid.

它抛出 org.codehaus.jackson.map.JsonMappingException，但我不知道如何或在哪里捕获此异常.我想捕获这个异常并发送回适当的错误响应.

It throws org.codehaus.jackson.map.JsonMappingException, but I don't how to or where to catch this exception. I want to catch this exception and send back appropriate error response.

@JsonInclude(JsonInclude.Include.NON_NULL)
@Generated("org.jsonschema2pojo")
@JsonPropertyOrder({
        "name",
        "id"
})
public class Customer {
    @JsonProperty("name")
    private String name;

    @JsonProperty("id")
    private String id;
     <setter/getter code>
}

public class MyService {
   @POST
    @Consumes(MediaType.APPLICATION_JSON)
    public final Response createCustomer(@Context HttpHeaders headers,
            Customer customer) {
        System.out.println("Customer data: " + customer.toString());
        return Response.ok("customer created").build();
    }
}

一切正常，但如果 json 主体格式不正确，则会引发 JsonMappingException 异常.我想捕捉这个异常.

Everything works fine, but if json body is not well formed then it throws JsonMappingException exception. I want to catch this exception.

推荐答案

最终对我有用的是为 JsonMappingException 声明一个 ExceptionMapper 提供程序，例如

What finally worked for me was to declare an ExceptionMapper provider for JsonMappingException, such as

import org.codehaus.jackson.map.JsonMappingException;
import org.springframework.stereotype.Component;

import javax.ws.rs.core.Response;
import javax.ws.rs.ext.ExceptionMapper;
import javax.ws.rs.ext.Provider;

@Component
@Provider
public class JsonMappingExceptionMapper implements ExceptionMapper<JsonMappingException> {
    @Override
    public Response toResponse(JsonMappingException exception) {
        return Response.status(Response.Status.BAD_REQUEST).build();
    }
}

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