如何获取 Jersey JaxRS 中的所有查询参数?
我正在构建一个通用 Web 服务，需要将所有查询参数抓取到一个字符串中以供以后解析.我该怎么做?
I am building a generic web service and need to grab all the query parameters into one string for later parsing. How can I do this?
推荐答案
您可以通过 @QueryParam("name") 访问单个参数或通过上下文访问所有参数:
You can access a single param via @QueryParam("name") or all of the params via the context:
@POST
public Response postSomething(@QueryParam("name") String name, @Context UriInfo uriInfo, String content) {
MultivaluedMap<String, String> queryParams = uriInfo.getQueryParameters();
String nameParam = queryParams.getFirst("name");
}
关键是 @Context jax-rs注解，可用于访问:
The key is the @Context jax-rs annotation, which can be used to access:
UriInfo、请求、HttpHeaders、安全上下文，提供者
UriInfo, Request, HttpHeaders, SecurityContext, Providers
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