在 Java 中使用 switch 的问题
我不明白为什么它总是返回 arg1 的值.我正在构建一个重量转换器.
I can't figure out why it's always returning the value of arg1. I'm building a weight converter.
public double convert(double arg1,int arg2,int arg3) {
// arg1 = amount, arg2 = from, arg3 = to
double milligram = 1;
double gram = 1000;
double ounce = 28349.5;
double pound = 453592;
double answer = 0;
switch(arg2) {
case 0: switch(arg3) { // if milligram
case 0: answer = (arg1 * milligram) / milligram;
case 1: answer = (arg1 * milligram) / gram;
case 2: answer = (arg1 * milligram) / ounce;
case 3: answer = (arg1 * milligram) / pound;
}
case 1: switch(arg3) { // if gram
case 0: answer = (arg1 * gram) / milligram;
case 1: answer = (arg1 * gram) / gram;
case 2: answer = (arg1 * gram) / ounce;
case 3: answer = (arg1 * gram) / pound;
}
case 2: switch(arg3) { // if ounce
case 0: answer = (arg1 * ounce) / milligram;
case 1: answer = (arg1 * ounce) / gram;
case 2: answer = (arg1 * ounce) / ounce;
case 3: answer = (arg1 * ounce) / pound;
}
case 3: switch(arg3) { // if pound
case 0: answer = (arg1 * pound) / milligram;
case 1: answer = (arg1 * pound) / gram;
case 2: answer = (arg1 * pound) / ounce;
case 3: answer = (arg1 * pound) / pound;
}
} // end arg2 switch
return answer;
}
我在逻辑上的某个地方搞砸了,但我看不出在哪里.任何帮助将不胜感激.
I messed up somewhere in my logic, but I'm failing to see where. Any help would be appreciated.
推荐答案
你缺少 break
语句:
case 0:
answer = (arg1 * milligram) / milligram;
break;
...
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