在switch语句中,为什么所有的case都被执行了?
我有这个代码和我从这个 switch 语句ordinal-characters">post,它工作得非常好:
I have this code with the switch
statement which I got from this post, and it works absolutely fine:
String getOrdinal(final int day) {
if (day >= 11 && day <= 13) {
return "th";
}
switch (day % 10) {
case 1: return "st";
case 2: return "nd";
case 3: return "rd";
default: return "th";
}
}
但如果我将其更改为类似以下的内容,它就会中断,因为除了 case 1
之外的所有情况都会被执行:
But if I change it to something like the following, it breaks, as all the cases besides case 1
gets executed:
static String getOrdinal(final int day) {
StringBuilder ordinalBuilder = new StringBuilder();
ordinalBuilder.append("<sup>");
if (day >= 11 && day <= 13) {
ordinalBuilder.append("th") ;
}
switch (day % 10) {
case 1: ordinalBuilder.append("st");
case 2: ordinalBuilder.append("nd");
case 3: ordinalBuilder.append("rd");
default: ordinalBuilder.append("th");
}
ordinalBuilder.append("</sup>");
return ordinalBuilder.toString();
}
当我传入 2
时,这将打印 2.我尝试将构建器更改为缓冲区,但我得到了相同的响应......这可能是一个错误还是我犯了一些错误?
This prints 2<sup>ndrdth</sup>
when I pass in 2
. I tried changing the builder to buffer but I got the same response... Could this be a bug or am I making some mistake?
推荐答案
这是您代码中的错误.你忘了在每个 case
后面加上一个 break
:
It's a bug in your code. You forgot to put in a break
after each case
:
switch (day % 10) {
case 1: ordinalBuilder.append("st"); break;
case 2: ordinalBuilder.append("nd"); break;
case 3: ordinalBuilder.append("rd"); break;
default: ordinalBuilder.append("th"); break;
}
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