获取数字位数的最快方法?
我确实检测到了数字上的位数.例如，329586 有 6 个数字.
I have do detect the amount of digits on a number. For example, 329586 has 6 digits.
我所做的只是将数字解析为字符串，并获取字符串长度，例如:
What I done, is simply parsing the number to string, and getting the string length, like:
number.toString().length()
但是，有没有最快的方法来计算数字的位数?我必须多次使用这种方法，所以我认为使用 toString() 会影响性能.
But, is there a fastest way to count digits on a number? I have to use this method several times, so I think using toString() can impact performance.
谢谢.
推荐答案
Math.floor(Math.log10(number) + 1)
// or just (int) Math.log10(number) + 1
例如:
int number = 123456;
int length = (int) Math.log10(number) + 1;
System.out.println(length);
输出:
6
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