从三个点找到圆心的算法是什么?
我在圆周上有三个点:
pt A = (A.x, A.y);
pt B = (B.x, B.y);
pt C = (C.x, C.y);
如何计算圆心?
在 Processing (Java) 中实现它.
Implementing it in Processing (Java).
我找到了答案并实施了一个可行的解决方案:
I found the answer and implemented a working solution:
pt circleCenter(pt A, pt B, pt C) {
float yDelta_a = B.y - A.y;
float xDelta_a = B.x - A.x;
float yDelta_b = C.y - B.y;
float xDelta_b = C.x - B.x;
pt center = P(0,0);
float aSlope = yDelta_a/xDelta_a;
float bSlope = yDelta_b/xDelta_b;
center.x = (aSlope*bSlope*(A.y - C.y) + bSlope*(A.x + B.x)
- aSlope*(B.x+C.x) )/(2* (bSlope-aSlope) );
center.y = -1*(center.x - (A.x+B.x)/2)/aSlope + (A.y+B.y)/2;
return center;
}
推荐答案
这可能是一个相当深入的计算.这里有一个简单的分步说明:http://paulbourke.net/geometry/circlesphere/.一旦你有了圆的方程，你就可以简单地把它变成一个包含 H 和 K 的形式.点 (h,k) 将是圆心.
It can be a rather in depth calculation. There is a simple step-by-step here: http://paulbourke.net/geometry/circlesphere/. Once you have the equation of the circle, you can simply put it in a form involving H and K. The point (h,k) will be the center.
(在链接处向下滚动一点以获取方程式)
(scroll down a little ways at the link to get to the equations)
相关文章