如何使用 Mockito 或任何其他相关的 Java 框架来模拟超类方法

2022-01-14 00:00:00 mocking mockito java junit powermock

我的场景如下

class SuperClass{
   public void run(){
      System.out.println("I am running in Super class");
   }
}

class ChildClass extends SuperClass{
  public void childRunner(){
     System.out.println("Step 1");
     System.out.println("Step 2");
     **run();**
     System.out.println("Last Step");
  }
}

现在我想模拟 ChildClasschildRunner() 方法,因为这个方法在内部调用超类方法,我需要一些帮助/一段代码来说明如何模拟 ChildClasschildRunner() 方法中存在的 run() 方法.

Now I want to mock the childRunner() method of ChildClass and since this method internally calls the super class method, i need some help/piece of code on how to mock the run() method which is present in the childRunner() method of ChildClass.

推荐答案

理想情况下,您应该优先考虑组合而不是继承".

Ideally, you should "favor composition over inheritance".

如果你没有这个选项,你可以使用 doNothing,它基本上告诉 Mockito 在调用 mock/spy 对象中的方法时什么都不做.这也讨论过这里

If you don't have this option you could use doNothing which basically tells Mockito to do nothing when a method in a mock/spy object is called. This was also discussed here

以下代码示例应该会有所帮助

Following code example should help

@Test
public void tst() {
    ChildClass ch = Mockito.spy(new ChildClass());
    Mockito.doNothing().when((SuperClass)ch).run();
    ch.childRunner();

}

class SuperClass{
    public void run(){
        System.out.println("I am running in Super class");
    }
}

class ChildClass extends SuperClass{
    public void childRunner(){
        System.out.println("Step 1");
        run();
        System.out.println("Last Step");
    }
}

输出:

Step 1
Last Step

如果你使用 super.run();这行不通

In case you use super.run(); this won't work

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