Java 类在 Jar 中读取 Yaml

2022-01-14 00:00:00 yaml java jar

我正在尝试从 jar 中的另一个类读取我的 jar 中的文件.但是我不断收到相同的错误: Caught: class java.io.FileNotFoundException while trying to read metrics: metrics.yml

I am trying to read a file inside my jar from another class inside the jar. However I am continually getting the same error: Caught: class java.io.FileNotFoundException while attempting to read metrics: metrics.yml

起初我让我的代码做这样的事情，假设它来自类的路径:

At first I had my code do something like this, assuming it was from the path of the class:

String yamlPath = ".." + File.separator + ".." + File.separator + ".." + File.separator + ".." + File.separator + "myYaml.yml";

InputStream in = new FileInputStream(new File(yamlPath));
InputStreamReader isr = new InputStreamReader(in);
BufferedReader input = new BufferedReader(isr);
yamlObj = (HashMap) javaYAML.load(input);

我也这样做了，假设它可能会从罐子底部走路径:

I also did this assuming it might take the path from the base of the jar:

String yamlPath = "myYaml.yml";

InputStream in = new FileInputStream(new File(yamlPath));
InputStreamReader isr = new InputStreamReader(in);
BufferedReader input = new BufferedReader(isr);
yamlObj = (HashMap) javaYAML.load(input);

然后我注意到了这个线程 How to read a file fromjar in Java? 发现我的路径前需要一个/".我也使用斜线尝试了上述两种方法.

I then noticed this thread How to read a file from jar in Java? and found out that I needed a "/" before my path. I tried both methods above using the slash as well.

String yamlPath = File.seperator + ".." + File.separator + ".." + File.separator + ".." + File.separator + ".." + File.separator + "myYaml.yml";

OR

String yamlPath = File.seperator + "myYaml.yml";

我现在完全不知道如何处理这个错误.关于 jar 结构有什么我没有得到的吗?为什么找不到我的文件.提前感谢您提供任何帮助/信息.

I am completely lost on what to do about this error now. Is there something I am not getting about the jar structure? Why can my file not be found. Thanks in advance for any help / information.

抱歉，我忘了提到它在 JAR 中的位置:该类位于以下路径中:com/a/b/c/myclass.classyaml 位于以下路径:myYaml.yml

Sorry, I forgot to mention where it is in the JAR: The class is in the following path: com/a/b/c/myclass.class The yaml is in the following path: myYaml.yml

推荐答案

Jar里面的文件不再是File，用这个改变inputStream的创建

File inside Jar is no longer a File, Change inputStream creation with this

InputStream in = YourClass.class.getResourceAsStream("myYaml.yml");

假设您的 .yml 文件位于 jar 的根目录

Assuming your .yml file is at root of jar

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