多对多关系的属性(休眠)
我有实体类 A 和 C.它们映射表 tblA 和 tblC 并且它们之间具有多对多关系，而 tblB 在它们之间进行映射.tblB 包含 A_ID、C_ID 和 SetDate，最后一个是设置的日期，因此是关系的一个属性.我的问题是，我如何最好地映射这个属性?目前它们未映射，如下所示:
I have entity classes A and C. They are mapping the tables tblA and tblC and have a many-to-many relationship between them, with tblB to map between them. tblB contains A_ID, C_ID and SetDate, the last one being the date it was set, thus an attribute to the relationship. My question is, how do I best map in this attribute? At the moment they're unmapped, like this:
答:
@ManyToMany(targetEntity=C.class, cascade={ CascadeType.PERSIST, CascadeType.MERGE } )
@JoinTable(name="tblB", joinColumns=@JoinColumn(name="A_ID"), inverseJoinColumns=@JoinColumn(name="C_ID") )
private Collection<C> Cs;
C:
@ManyToMany( cascade = {CascadeType.PERSIST, CascadeType.MERGE}, mappedBy = "Cs", targetEntity = A.class )
private Collection<A> As;
我应该如何从中获得 tblB.SetDate?
How should I get tblB.SetDate out of this?
干杯
尼克
推荐答案
据我所知，不可能这样映射，你必须切换到 One-To- 多对一关系，中间是你的 B.您的日期将是 B 的一个属性.
From what I know, it is not possible to map it this way, you have to switch to One-To-Many and a Many-To-One relationships, with your B in the middle. Your date will be an attribute of B.
由于缺乏进化性，Hibernate 文档建议一般避免多对多，并从一开始就使用这两种关系.
For this lack of evolutivity, the Hibernate documentation recommends to avoid the Many-To-Many in general, and use the two relationships from the beginning.
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