如何在 Java 中将 char 转换为 int?
(我是 Java 编程新手)
(I'm new at Java programming)
例如:
char x = '9';
我需要得到撇号中的数字,即数字 9 本身.我尝试执行以下操作,
and I need to get the number in the apostrophes, the digit 9 itself. I tried to do the following,
char x = 9;
int y = (int)(x);
但是没有用.
那么我应该怎么做才能得到撇号中的数字呢?
So what should I do to get the digit in the apostrophes?
推荐答案
排列ASCII表,使得字符'9'
的值比'的值大90'
;字符'8'
的值比'0'
的值大8;等等.
The ASCII table is arranged so that the value of the character '9'
is nine greater than the value of '0'
; the value of the character '8'
is eight greater than the value of '0'
; and so on.
所以你可以通过减去'0'
得到一个十进制数字char的int值.
So you can get the int value of a decimal digit char by subtracting '0'
.
char x = '9';
int y = x - '0'; // gives the int value 9
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