将异步任务发送到在其他线程中运行的循环

问题描述

如何异步插入任务以在另一个线程中运行的asyncio事件循环中运行？

我的动机是支持解释器中的交互式异步工作负载。我无法挡路主REPL帖子。

示例

我目前有缺陷的理解是，以下方法应该是可行的。为什么不是呢？实现上述目标的更好方法是什么？

import asyncio
from threading import Thread

loop = asyncio.new_event_loop()

def f(loop):
    asyncio.set_event_loop(loop)
    loop.run_forever()

t = Thread(target=f, args=(loop,))
t.start()    

@asyncio.coroutine
def g():
    yield from asyncio.sleep(1)
    print('Hello, world!')

asyncio.async(g(), loop=loop)

---

解决方案

您必须使用call_soon_threadsafe计划来自不同线程的回调：

import asyncio
from threading import Thread

loop = asyncio.new_event_loop()

def f(loop):
    asyncio.set_event_loop(loop)
    loop.run_forever()

t = Thread(target=f, args=(loop,))
t.start()    

@asyncio.coroutine
def g():
    yield from asyncio.sleep(1)
    print('Hello, world!')

loop.call_soon_threadsafe(asyncio.async, g())

有关详细信息，请参阅https://docs.python.org/3/library/asyncio-dev.html#asyncio-multithreading。

编辑：支持异步工作负载的解释器示例

# vim: filetype=python3 tabstop=2 expandtab

import asyncio as aio
import random

@aio.coroutine
def async_eval(input_, sec):
  yield from aio.sleep(sec)
  print("")
  try:
    result = eval(input_)
  except Exception as e:
    print("< {!r} does not compute >".format(input_))
  else:  
    print("< {!r} = {} >".format(input_, result))

@aio.coroutine
def main(loop):
  while True:
    input_ = yield from loop.run_in_executor(None, input, "> ")

    if input_ == "quit":
      break
    elif input_ == "":
      continue
    else:
      sec = random.uniform(5, 10)
      print("< {!r} scheduled for execution in {:.02} sec>".format(input_, sec))
      aio.async(async_eval(input_, sec))

loop = aio.get_event_loop()

loop.run_until_complete(main(loop))
loop.close()