如何获得以下格式化输出?
我编写代码以获得以下格式化输出,但是当我输入两位数的行数时,输出格式会发生变化.为什么?我该如何解决这个问题?
I wrote the code to get the following formatted output, but when I enter number of rows in double digits, the output format changes. Why? How can I fix this?
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
这是我的代码:
import java.util.*;
class PTri {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the no. of rows for which " +
"triangle has to be constructed");
int numrow = sc.nextInt();
for (int i = 1; i <= numrow; i++) {
for (int j = 1; j <= numrow - i; j++) {
System.out.print(" ");
}
for (int k = 1; k < i * 2; k++) {
System.out.print(Math.min(k, i * 2 - k) + " ");
}
System.out.println();
}
}
}
推荐答案
这是因为两位数的值会改变整个架构.集合会向右移动一个位置.所以你可以提出这样的条件.我在数字之间添加了一个额外的空格以提高可见性.
It's because the value in double digit will change the whole architecture.The set will shift to right one place. So you can put a condition like this. I have added one extra space between numbers to improve visibility.
import java.util.*;
class PTri {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the no. of rows for which " +
"triangle has to be constructed");
int numrow = sc.nextInt();
for (int i = 1; i <= numrow; i++) {
for (int j = 1; j <= (numrow - i); j++) {
System.out.print(" ");
}
for (int k = 1; k < i * 2; k++) {
int temp = Math.min(k, i * 2 - k);
if (temp > 9) {
System.out.print(temp + " ");
} else {
System.out.print(temp + " ");
}
}
System.out.println();
}
}
}
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