在 Object.wait() 之前调用 Object.notify()
如果没有线程在等待，使用 Object.wait() ，任何对 Object.notify() 或 Object.notifyAll() 的调用 无效.我有一个场景，如果我在等待集为空时调用 Object.notify()，随后对 Object.wait() 的调用不应将线程置于等待.如何实现?信号量可能是我能想到的一种解决方案.有没有更优雅的解决方案?
If there is no thread which is waiting, using Object.wait() , any calls to Object.notify() or Object.notifyAll() have no effect. I have a scenario in which if I call Object.notify() when the wait set is empty, a subsequent call to Object.wait() should not put the thread to wait. How can this be accomplished? Semaphores may be one solution I can think of. Is there a more elegant solution?
推荐答案
这种场景似乎非常适合 Semaphore.调用 Semaphore.release() 而不是 notify() 和 Semaphore.acquire() 而不是等待.
This kind of scenario seems to be a perfect fit for a Semaphore. Call Semaphore.release() instead of notify() and Semaphore.acquire() instead of wait.
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