使用 Java 将文件上传和 POST 到 PHP 页面
我需要一种上传文件并将其发布到 php 页面的方法...
I need a way to upload a file and POST it into php page...
我的php页面是:
<?php
$maxsize = 10485760;
$array_estensioni_ammesse=array('.tmp');
$uploaddir = 'uploads/';
if (is_uploaded_file($_FILES['file']['tmp_name']))
{
if($_FILES['file']['size'] <= $maxsize)
{
$estensione = strtolower(substr($_FILES['file']['name'], strrpos($_FILES['file']['name'], "."), strlen($_FILES['file']['name'])-strrpos($_FILES['file']['name'], ".")));
if(!in_array($estensione, $array_estensioni_ammesse))
{
echo "File is not valid!
";
}
else
{
$uploadfile = $uploaddir . basename($_FILES['file']['name']);
echo "File ". $_FILES['file']['name'] ." uploaded successfully.
";
if (move_uploaded_file($_FILES['file']['tmp_name'], $uploadfile))
{
echo "File is valid, and was successfully moved.
";
}
else
print_r($_FILES);
}
}
else
echo "File is not valid!
";
}
else
{
echo "Upload Failed!!!";
print_r($_FILES);
}
?>
我在我的桌面应用程序中使用这个 java 代码:
and i use this java code in my desktop application:
HttpURLConnection httpUrlConnection = (HttpURLConnection)new URL("http://www.mypage.org/upload.php").openConnection();
httpUrlConnection.setDoOutput(true);
httpUrlConnection.setRequestMethod("POST");
OutputStream os = httpUrlConnection.getOutputStream();
Thread.sleep(1000);
BufferedInputStream fis = new BufferedInputStream(new FileInputStream("tmpfile.tmp"));
long totalByte = fis.available();
long byteTrasferred = 0;
for (int i = 0; i < totalByte; i++) {
os.write(fis.read());
byteTrasferred = i + 1;
}
os.close();
BufferedReader in = new BufferedReader(
new InputStreamReader(
httpUrlConnection.getInputStream()));
String s = null;
while ((s = in.readLine()) != null) {
System.out.println(s);
}
in.close();
fis.close();
但我总是收到上传失败!!!"消息.
But I receive always the "Upload Failed!!!" message.
推荐答案
即使线程很老了,可能还是有人在寻找更简单的方法来解决这个问题(比如我:))
Even though the thread is very old, there may still be someone around looking for a more easy way to solve this problem (like me :))
经过一番研究,我找到了一种在不更改原始海报 Java 代码的情况下上传文件的方法.您只需要使用以下 PHP 代码:
After some research I found a way to uplaod a file without changing the original poster's Java-Code. You just have to use the following PHP-code:
<?php
$filename="abc.xyz";
$fileData=file_get_contents('php://input');
$fhandle=fopen($filename, 'wb');
fwrite($fhandle, $fileData);
fclose($fhandle);
echo("Done uploading");
?>
此代码只是获取 java 应用程序发送的原始数据并将其写入文件.然而,有一个问题:你没有得到原始文件名,所以你必须以其他方式传输它.
This code is just fetching the raw data sent by the java-application and writing it into a file. There is, however one problem: You dont get the original filename, so you have to transmit it somehow else.
我通过使用 GET 参数解决了这个问题,这对 Java 代码进行了一些必要的更改:
I solved this problem by using a GET-Parameter, which makes a little change in the Java-code necessary:
HttpURLConnection httpUrlConnection = (HttpURLConnection)new URL("http://www.mypage.org/upload.php").openConnection();
更改为
HttpURLConnection httpUrlConnection = (HttpURLConnection)new URL("http://www.mypage.org/upload.php?filename=abc.def").openConnection();
在您的 PHP 脚本中更改行
In your PHP-script you change the line
$filename="abc.xyz";
到
$filename=$_GET['filename'];
这个解决方案不使用任何外部库,在我看来比其他一些发布的更简单......
This solution doesn't use any external librarys and seems to me much more simple than some of the other posted ones...
希望我能帮助任何人:)
Hope I could help anyone:)
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