Java二进制补码到整数
我知道用 Integer.toBinaryString(355) = 0000000101100011 将十进制转换为二进制Integer.toBinaryString(-355) = 1111111010011101(我取 32 位结果的低 16 位).
I know that converting a decimal to binary with Integer.toBinaryString(355) = 0000000101100011 and
Integer.toBinaryString(-355) = 1111111010011101 (where I take the lower 16 bits of the 32 bit result).
我想做的是另一种方式，采用 16 位二进制补码二进制字符串并转换为十进制.
What I would like to do is the other way and take a 16-bit twos's complement binary string and to convert to decimal.
即
0000000000110010 = 50
1111111111001110 = -50
而不是1111111111001110 = 65486
我该怎么做?
推荐答案
需要将结果读入short.
short res = (short)Integer.parseInt("1111111111001110", 2);
System.out.println(res);
这个打印-50.
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