比较两个字节数组?(爪哇)

2022-01-09 00:00:00 binary java

我有一个字节数组，里面有一个~已知的二进制序列.我需要确认二进制序列是它应该是什么.除了 == 之外，我还尝试了 .equals，但都没有成功.

I have a byte array with a ~known binary sequence in it. I need to confirm that the binary sequence is what it's supposed to be. I have tried .equals in addition to ==, but neither worked. 

byte[] array = new BigInteger("1111000011110001", 2).toByteArray();
if (new BigInteger("1111000011110001", 2).toByteArray() == array){
    System.out.println("the same");
} else {
    System.out.println("different'");
}

推荐答案

在你的例子中，你有:

if (new BigInteger("1111000011110001", 2).toByteArray() == array)

在处理对象时，java中的==会比较引用值.您正在检查 toByteArray() 返回的对数组的引用是否与 array 中保存的引用相同，这当然不可能是真的.此外，数组类不会覆盖 .equals() 因此其行为是 Object.equals() 的行为，它也只比较参考值.

When dealing with objects, == in java compares reference values. You're checking to see if the reference to the array returned by toByteArray() is the same as the reference held in array, which of course can never be true. In addition, array classes don't override .equals() so the behavior is that of Object.equals() which also only compares the reference values.

为了比较两个数组的内容，数组类

byte[] array = new BigInteger("1111000011110001", 2).toByteArray();
byte[] secondArray = new BigInteger("1111000011110001", 2).toByteArray();
if (Arrays.equals(array, secondArray))
{
    System.out.println("Yup, they're the same!");
}

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