子集和找到所有加起来为一个数字的子集

I have been learning dynamic programming, and I want to take the classic subset sum problem a little further by printing out all the subsets which add up to a number. How exactly would I go about doing this? As of now, I know how to print true or false based on whether there is a subset that adds up to it

    public static boolean hasSum(int [] array, int sum)
{
    int len = array.length;
    boolean[][] table = new boolean[sum+1][len+1];

    int i;

    for( i = 0; i <= len; i++ )
        table[0][i] = true;

    for( i = 1; i <= sum; i++ )
        table[i][0] = false;

    for( i = 1; i <= sum; i++ )
    {
        for( int j = 1; j <= len; j++ )
        {
            table[i][j] = table[i][j-1]; 

            if( !table[i][j] && i >= array[j-1] )
                table[i][j] = table[i-array[j-1]][j-1];
        }
    }        

    return table[sum][len];
}

如果可能，我想返回一个包含所有子集的数组.