将浮点数格式化为 n 位小数
我需要将浮点数格式化为n"个小数位.
I need to format a float to "n"decimal places.
正在尝试 BigDecimal,但返回值不正确...
was trying to BigDecimal, but the return value is not correct...
public static float Redondear(float pNumero, int pCantidadDecimales) {
// the function is call with the values Redondear(625.3f, 2)
BigDecimal value = new BigDecimal(pNumero);
value = value.setScale(pCantidadDecimales, RoundingMode.HALF_EVEN); // here the value is correct (625.30)
return value.floatValue(); // but here the values is 625.3
}
我需要返回一个带有我指定的小数位数的浮点值.
I need to return a float value with the number of decimal places that I specify.
我需要 Float
值返回而不是 Double
I need Float
value return not Double
.
推荐答案
你也可以传入float值,使用:
You may also pass the float value, and use:
String.format("%.2f", floatValue);
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