Bootstrap V5手动调用不起作用的模式myModal.show()(普通的javascript)

2022-08-25 00:00:00 javascript bootstrap-5

在Bootstrap 5中手动调用模式的正确方式是什么?

我想在页面打开时显示模式。我试过了:

我的模式

<div class="modal fade" id="myModal" tabindex="-1" aria-labelledby="exampleModalLabel" aria-hidden="true">
  <div class="modal-dialog">
    <div class="modal-content">
        ... 
        ... 
        ... 
    </div>
  </div>
</div>

我的脚本是

var myModal = document.getElementById('myModal');
document.onreadystatechange = function() {
   
    myModal.show();
}

但在控制台日志中收到此错误:

 myModal.show is not a function
    at HTMLDocument.document.onreadystatechange

解决方案

模式插件通过数据属性或JavaScript按需切换隐藏内容。它还会在中添加.modal-Open以覆盖默认滚动行为,并生成.modal-Backdown以提供一个单击区,用于在模式之外单击时取消所显示的模式。 [source]

如何通过Vanilla JavaScript使用

使用一行JavaScript创建一个模式:

var myModal = new bootstrap.Modal(document.getElementById('myModal'), options)

source

快速示例:

数据-lang="js"数据-隐藏="假"数据-控制台="真"数据-巴贝尔="假">
var myModal = new bootstrap.Modal(document.getElementById("exampleModal"), {});
document.onreadystatechange = function () {
  myModal.show();
};
<!DOCTYPE html>
<html lang="en">
  <head>

    <meta charset="utf-8" />
    <meta
      name="viewport"
      content="width=device-width, initial-scale=1, shrink-to-fit=no"
    />


    <link
      rel="stylesheet"
      href="https://stackpath.bootstrapcdn.com/bootstrap/5.0.0-alpha1/css/bootstrap.min.css"
      integrity="sha384-r4NyP46KrjDleawBgD5tp8Y7UzmLA05oM1iAEQ17CSuDqnUK2+k9luXQOfXJCJ4I"
      crossorigin="anonymous"
    />
    <title>Hello, world!</title>
  </head>
  <body>

    <div
      class="modal fade"
      id="exampleModal"
      tabindex="-1"
      role="dialog"
      aria-labelledby="exampleModalLabel"
      aria-hidden="true"
    >
      <div class="modal-dialog">
        <div class="modal-content">
          <div class="modal-header">
            <h5 class="modal-title" id="exampleModalLabel">Modal title</h5>
            <button
              type="button"
              class="close"
              data-dismiss="modal"
              aria-label="Close"
            >
              <span aria-hidden="true">&times;</span>
            </button>
          </div>
          <div class="modal-body">
            ...
          </div>
          <div class="modal-footer">
            <button
              type="button"
              class="btn btn-secondary"
              data-dismiss="modal"
            >
              Close
            </button>
            <button type="button" class="btn btn-primary">Save changes</button>
          </div>
        </div>
      </div>
    </div>

    <!-- JavaScript and dependencies -->
    <script
      src="https://cdn.jsdelivr.net/npm/popper.js@1.16.0/dist/umd/popper.min.js"
      integrity="sha384-Q6E9RHvbIyZFJoft+2mJbHaEWldlvI9IOYy5n3zV9zzTtmI3UksdQRVvoxMfooAo"
      crossorigin="anonymous"
    ></script>
    <script
      src="https://stackpath.bootstrapcdn.com/bootstrap/5.0.0-alpha1/js/bootstrap.min.js"
      integrity="sha384-oesi62hOLfzrys4LxRF63OJCXdXDipiYWBnvTl9Y9/TRlw5xlKIEHpNyvvDShgf/"
      crossorigin="anonymous"
    ></script>

    <script src="./app.js"></script>
  </body>
</html>

至于您的代码,您没有按照正确的方式在Vanilla JavaScript中显示/切换模式。为什么当myModal只是一个DOM元素时,您希望myModal.show()发生?

相关文章