如何在Reaction导航6中分别处理两个抽屉？

我已经创建了两个抽屉导航器

const MenuDrawerRight = createDrawerNavigator();
const MenuDrawerLeft = createDrawerNavigator();

function RightDrawerScreens() {
  return (
    <MenuDrawerRight.Navigator
      drawerContent={props => <RightDrawerContent {...props} />}
      screenOptions={{
        headerShown: false,
        drawerType: 'back',
        drawerPosition: 'right',
      }}>
      <MenuDrawerRight.Screen name="Menu" component={Menu} />
      <MenuDrawerRight.Screen name="DashBoard" component={DashBoard} />
    </MenuDrawerRight.Navigator>
  );
}

function LeftDrawerScreens() {
  return (
    <MenuDrawerLeft.Navigator
      drawerContent={props => <LeftDrawerContent {...props} />}
      screenOptions={{headerShown: false}}>
      <MenuDrawerLeft.Screen name="Menu" component={Menu} />
      <MenuDrawerLeft.Screen name="DashBoard" component={DashBoard} />
    </MenuDrawerLeft.Navigator>
  );
}

已创建用于获取抽屉内容的单独组件。

现在如何将这两个抽屉包装在一个导航器中，以及如何分别打开这两个抽屉(单击第一个按钮打开一个抽屉，单击第二个按钮打开第二个抽屉)

如果需要任何其他详细信息，请在评论区询问。

---

解决方案

我把一个抽屉包在另一个抽屉里，就像这样

function MenuDrawerScreen() {
  return (
    <MenuDrawerRight.Navigator
      drawerContent={props => <RightDrawerContent {...props} />}
      screenOptions={{
        headerShown: false,
        drawerType: 'back',
        drawerPosition: 'right',
      }}
      initialRouteName="MenuScreen">
      <MenuDrawerRight.Screen name="MenuScreen" component={Menu} />
      <MenuDrawerRight.Screen name="DashBoard" component={DashBoard} />
      <MenuDrawerRight.Screen name="LeftDrawer" component={LeftDrawerScreens} />
      <MenuDrawerRight.Screen name="Profile" component={Profile} />
      <MenuDrawerRight.Screen name="Logout" component={Logout} />
    </MenuDrawerRight.Navigator>
  );
}

function LeftDrawerScreens() {
  return (
    <MenuDrawerLeft.Navigator
      drawerContent={props => <LeftDrawerContent {...props} />}
      screenOptions={{headerShown: false}}>
      <MenuDrawerLeft.Screen name="Menu" component={MenuDrawerScreen} />
    </MenuDrawerLeft.Navigator>
  );
}

，然后使用navigation.getParent().openDrawer()打开父抽屉，使用navigation.openDrawer()打开子抽屉