按多个属性对对象进行分组并合并数组属性
在示例中,我使用Each遍历选择字段并创建数据数组,我需要对2个属性year
和cabin
进行分组,并且属性months
是我想要合并的数组,问题是我在获取所需结果时遇到了一些问题:
JSFIDDLE:http://jsfiddle.net/tc39xu6b/2/
我得到的结果:
[
{
"year": "2021",
"cabin": "1",
"months": [
"1",
"2"
]
},
{
"year": "2021",
"cabin": "1",
"months": [
"4"
]
},
{
"year": "2021",
"cabin": "2",
"months": [
"1",
"2"
]
},
{
"year": "2022",
"cabin": "1",
"months": [
"1",
"2"
]
},
{
"year": "2022",
"cabin": "1",
"months": [
"4"
]
},
{
"year": "2022",
"cabin": "2",
"months": [
"1",
"2"
]
}
]
这就是我需要的结果:
{
"2021": [
{"cabin":1, "months": ["1", "2","4"]},
{"cabin":2, "months": ["1", "2"]}
],
"2022": [
{"cabin":1, "months": ["1", "2","4"]},
{"cabin":2, "months": ["1", "2"]}
]
}
解决方案
这是相当正常的group by
情况。下面的代码片段使用reduce()
重构您的数组,但您可以直接将逻辑按原样放入函数中:http://jsfiddle.net/83st9wgh/
const input = [{ "year": "2021", "cabin": "1", "months": ["1", "2"] }, { "year": "2021", "cabin": "1", "months": ["4"] }, { "year": "2021", "cabin": "2", "months": ["1", "2"] }, { "year": "2022", "cabin": "1", "months": ["1", "2"] }, { "year": "2022", "cabin": "1", "months": ["4"] }, { "year": "2022", "cabin": "2", "months": ["1", "2"] }];
const result = input.reduce((acc, { year, cabin, months }) => {
const yearArray = (acc[year] ??= []);
let cIndex = yearArray.findIndex(o => o.cabin === cabin);
if (cIndex === -1) {
cIndex = yearArray.push({ cabin, months: [] }) - 1;
}
const monthsArray = yearArray[cIndex].months;
yearArray[cIndex].months = [...new Set(monthsArray.concat(months))];
return acc;
}, {});
console.log(JSON.stringify(result, null, 2));
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