带有onclick的按钮在Reaction中只工作一次

2022-03-03 00:00:00 reactjs javascript jsx

我需要在Reaction应用程序中创建折叠菜单,但onclick的按钮只起作用一次。我创建了一个布尔变量,当我点击按钮时,它应该会更改。但我只能点击该按钮一次,此后<a>不起作用,它处于非活动状态:

let isOpened = false;

class Header extends React.Component {
  handleClick = () => {
    isOpened = !isOpened;
  };

  render() {
    const path = history.location && history.location.pathname;
    return (
      <div className={s['header-left']}>
        <div className={s.button}>
          <a href="#"  onClick={this.handleClick}>
            <FontAwesomeIcon icon={faBars} />
          </a>
        </div>

和折叠代码:

<Collapse isOpened={isOpened}>
        <nav className={`${s.menu} ${s.mobile}`}>
          <ul className={s['menu-ul']}>
            ...
          </ul>
        </nav>
      </Collapse>

解决方案

您的onClick工作正常,但它没有重新呈现您的Reaction组件。您需要将isOpened置于组件和全局变量的状态。请阅读this

class Header extends React.Component {
  constructor(props){
      super(props);

      this.state = {isOpened: false};
  }
  handleClick = () => {
    this.setState({isOpened: !this.state.isOpened});
  };

  render() {
    const path = history.location && history.location.pathname;
    return (
      <div className={s['header-left']}>
        <div className={s.button}>
          <a href="#"  onClick={this.handleClick}>
            <FontAwesomeIcon icon={faBars} />
          </a>
        </div>
   );
 }

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