查找数组中所有可能的子集组合?
我需要获取一个数组的所有可能子集,其中包含最少 2
个项目和未知的最大值.谁能帮帮我?
I need to get all possible subsets of an array with a minimum of 2
items and an unknown maximum. Anyone that can help me out a bit?
假设我有以下数组:
[1, 2, 3]
我如何得到这个?
[
[1, 2],
[1, 3],
[2, 3],
[1, 2, 3]
]
推荐答案
盗取后this JavaScript 组合生成器,我添加了一个参数来提供导致的最小长度,
After stealing this JavaScript combination generator, I added a parameter to supply the minimum length resulting in,
var combine = function(a, min) {
var fn = function(n, src, got, all) {
if (n == 0) {
if (got.length > 0) {
all[all.length] = got;
}
return;
}
for (var j = 0; j < src.length; j++) {
fn(n - 1, src.slice(j + 1), got.concat([src[j]]), all);
}
return;
}
var all = [];
for (var i = min; i < a.length; i++) {
fn(i, a, [], all);
}
all.push(a);
return all;
}
要使用,提供一个数组,以及所需的最小子集长度,
To use, supply an array, and the minimum subset length desired,
var subsets = combine([1, 2, 3], 2);
输出是,
[[1, 2], [1, 3], [2, 3], [1, 2, 3]]
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