在 JavaScript 中使用递归获取范围数

2022-01-24 00:00:00 递归 range javascript

我正在尝试使用递归来获取数字范围.有人可以向我解释为什么它不起作用吗?

I am trying to get the range of numbers using recursion. Can someone explain to me why it isn't working?

function range(x,y){
    var results = [];
    if(x === y){
        return results;
    }



return  results.push(range(x + 1,y));
}

range(1,5);

推荐答案

试试这个:

function rangeOfNumbers(startNum, endNum) {
 if (startNum - endNum === 0) {
  return [startNum];
 } else {
  const numbers = rangeOfNumbers(startNum + 1, endNum);    
  numbers.unshift(startNum);
  return numbers;
 }
};

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