在 JavaScript 中比较字符串时，为什么一个字符串比另一个大?
我从一本书中看到了这段代码:
I see this code from a book:
var a = "one";
var b = "four";
a>b; // will return true
但它没有提到为什么一"大于四".我试过 c = "a" 并且它小于 a 和 b.我想知道 JavaScript 如何比较这些字符串.
but it doesn't mention why "one" is bigger than "four". I tried c = "a" and it is smaller than a and b. I want to know how JavaScript compares these strings.
推荐答案
因为在许多编程语言中，字符串是比较的 按字典顺序.
Because, as in many programming languages, strings are compared lexicographically.
您可以将其视为字母顺序的更高级版本，区别在于该字母顺序仅涵盖 a 到 z 的 26 个字符.
You can think of this as a fancier version of alphabetical ordering, the difference being that alphabetic ordering only covers the 26 characters a through z.
这个答案是对java 问题，但逻辑完全一样.另一个不错的:字符串比较Logic".
This answer is in response to a java question, but the logic is exactly the same. Another good one: String Compare "Logic".
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