Javascript函数 - 将字符串参数转换为运算符

2022-01-21 00:00:00 function operators arguments javascript

抱歉,如果我的问题不清楚,不知道如何措辞!

我正在尝试创建一个函数,该函数接受两个数字和一个包含运算符(例如'+'、'-'、'*'、'/')的字符串.

I'm trying to create a function that takes two numbers and a string which contains an operator (e.g. '+', '-', '*', '/').

我在字符串上使用了 .valueOf() 来提取运算符,但是 num1 和 num2 参数似乎没有计算为传递的数字参数.为什么会这样?

I've used .valueOf() on the string to extract the operator, however the num1 and num2 arguments do not seem to evaluate to the passed number parameters. Why is this happening?

function calculate(num1, operator, num2) {
  return `num1 ${operator.valueOf()} num2`;
}
undefined


calculate(2, '+', 1);
"num1 + num2"         //result

推荐答案

如果我理解您的要求,您可以使用 eval() 来实现:

If I understand your requirements, you could use eval() to achieve this:

function calculate(num1, operator, num2) {
  return eval(`${num1} ${operator} ${num2}`);
}

console.log(calculate(2, '+', 1)); // 3

或者,您可以通过使用开关块来避免使用 eval(),它 将使您的代码更易于调试并且可能更安全:

Alternatively, you could avoid the use of eval() by using a switch block, which would make your code easier to debug and potentially more secure:

function calculate(num1, operator, num2) {
  switch (operator.trim()) { // Trim possible white spaces to improve reliability
    case '+':
      return num1 + num2
    case '-':
      return num1 - num2
    case '/':
      return num1 / num2
    case '*':
      return num1 * num2
  }
}

console.log(calculate(2, '+', 1)); // 3

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