Sequelize:如何使用左外连接对连接表执行 WHERE 条件

I'd like sequelize to fetch me all employees where they don't drive a vehicle, or if they do then the vehicle is not diesel.
So where VehicleID is null OR Vehicle.VehicleModel.IsDiesel = false

我目前的代码如下:

var employee = sequelize.define('employee', {
    ID: Sequelize.INTEGER,
    VehicleID: Sequelize.INTEGER
});

var vehicle = sequelize.define('vehicle', {
    ID: Sequelize.INTEGER,
    ModelID: Sequelize.INTEGER
});

var vehicleModel = sequelize.define('vehicleModel', {
    ID: Sequelize.INTEGER,
    IsDiesel: Sequelize.BOOLEAN
});

employee.belongsTo(vehicle);
vehicle.belongsTo(vehicleModel);

如果我运行以下命令:

options.include = [{
    model: model.Vehicle,
    attributes: ['ID', 'ModelID'],
        include: [
        {
            model: model.VehicleModel,
            attributes: ['ID', 'IsDiesel']
        }]
}];

employee
 .findAll(options)
 .success(function(results) {
     // do stuff
 });

Sequelize 执行左外连接以获取包含的表.所以我找到了会开车和不开车的员工.
只要我在选项中添加位置:

options.include = [{
    model: model.Vehicle,
    attributes: ['ID', 'ModelID'],
    include: [
        {
            model: model.VehicleModel,
            attributes: ['ID', 'IsDiesel']
            where: {
                IsDiesel: false
            }
        }]
}];

options.include = [{
    model: model.Vehicle,
    attributes: ['ID', 'ModelID'],
    include: [
        {
            model: model.VehicleModel,
            attributes: ['ID', 'IsDiesel']
            where: {
                IsDiesel: false
            },
            required: false
        }],
    required: false

}];