如何将回调函数中的值返回给调用者?
如何让这个小函数imageExists"返回 ajax 请求是否成功?
How can i make this little function "imageExists" return wether the ajax request was successful or not?
function imageExists(path){
$.ajax({
url: path,
type: 'HEAD',
error:
function(){
return false;
},
success:
function(){
return true;
}
});
}
推荐答案
我相信你必须使用同步模式并使用单独的a变量来存储返回值.
I believe you'll have to use synchronous mode and use a separate a variable for storing the return value.
function imageExists(path){
var isSuccess;
$.ajax({
url: path,
type: 'HEAD',
async: false,
error:
function(){
isSuccess = false;
return false;
},
success:
function(){
isSuccess = true;
return true;
}
});
return isSuccess;
}
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