Jquery 和 List 中的 switch 语句
我想知道我的方法是否有效且正确.但我的代码不起作用，我不知道为什么.
I would like to know if my approach is efficient and correct. my code is not working though, I don't know why.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js" type="text/javascript" charset="utf-8"></script>
<script type="text/javascript">
$(document).ready(function() {
function HotelQuery(HotelName) {
switch (HotelName) {
case 'TimelessHotel':
var strHotelName = 'Timeless Hotel';
var strHotelDesc = 'Hotel Description Timeless Hotel';
var strHotelPrice = ['980.00', '1,300.00', '1,600.00', '1,500.00', '1,800.00', '300.00', '150.00', '200.00'];
var strHotelRoomType = ['Single Room', 'Delux Room','Twin Room', 'Matrimonial Room', 'Presidential Suites', 'Extra Bed', 'Free Breakfast', 'Extra Person'];
; //end Timeless Hotel
case 'ParadiseInn':
var strHotelName = 'Paradise Inn';
var strHotelDesc = 'Hotel Description Paradise Inn';
var strHotelPrice = ['980.00', '1,300.00', '1,600.00', '1,500.00', '1,800.00', '300.00', '150.00', '200.00'];
var strHotelRoomType = ['Single Room', 'Delux Room','Twin Room', 'Matrimonial Room', 'Presidential Suites', 'Extra Bed', 'Free Breakfast', 'Extra Person'];
; //end Paradise Inn
case 'TetrisHotel':
var strHotelName = 'Tetris Hotel';
var strHotelDesc = 'Hotel Description Tetris Hotel';
var strHotelPrice = ['980.00', '1,300.00', '1,600.00', '1,500.00', '1,800.00', '300.00', '150.00', '200.00'];
var strHotelRoomType = ['Single Room', 'Delux Room','Twin Room', 'Matrimonial Room', 'Presidential Suites', 'Extra Bed', 'Free Breakfast', 'Extra Person'];
; //end Tetris Hotel
case 'JamstoneInn':
var strHotelName = 'Jamstone Inn';
var strHotelDesc = 'Hotel Description Jamstone Inn';
var strHotelPrice = ['980.00', '1,300.00', '1,600.00', '1,500.00', '1,800.00', '300.00', '150.00', '200.00'];
var strHotelRoomType = ['Single Room', 'Delux Room','Twin Room', 'Matrimonial Room', 'Presidential Suites', 'Extra Bed', 'Free Breakfast', 'Extra Person'];
; //end Jamstone Inn
}
};
});
</script>
<title>hotel query</title>
</head>
<body>
<a href="#" onclick="javascript: HotelQuery('TetrisHotel'); alert: (strHotelName, strHotelDesc, strHotelPrice);">Tetris Hotel Query</a>
</body>
</html>
推荐答案
你的代码不起作用，因为变量的作用域是函数 HotelQuery.我认为您可能想要做的是从函数返回一个具有属性的对象，并使用不显眼的 JavaScript 方法将点击事件处理程序绑定到 <a> 元素.
You code doesn't work because the variables are scoped to the function HotelQuery. I think what you might want to do is return an object with properties from the function, and also use the unobtrusive JavaScript approach to bind an click event handler to the <a> element.
类似
$(function() {
$('a').click(function() {
var hotel = HotelQuery('TetrisHotel');
alert(hotel.name) // alerts 'Tetris Hotel'
});
});
function HotelQuery(HotelName) {
var strHotelName;
var strHotelDesc;
var strHotelPrice;
var strHotelRoomType;
switch (HotelName) {
case 'TimelessHotel':
strHotelName = 'Timeless Hotel';
strHotelDesc = 'Hotel Description Timeless Hotel';
strHotelPrice = ['980.00', '1,300.00', '1,600.00', '1,500.00', '1,800.00', '300.00', '150.00', '200.00'];
strHotelRoomType = ['Single Room', 'Delux Room','Twin Room', 'Matrimonial Room', 'Presidential Suites', 'Extra Bed', 'Free Breakfast', 'Extra Person'];
break; //end Timeless Hotel
case 'ParadiseInn':
strHotelName = 'Paradise Inn';
strHotelDesc = 'Hotel Description Paradise Inn';
strHotelPrice = ['980.00', '1,300.00', '1,600.00', '1,500.00', '1,800.00', '300.00', '150.00', '200.00'];
strHotelRoomType = ['Single Room', 'Delux Room','Twin Room', 'Matrimonial Room', 'Presidential Suites', 'Extra Bed', 'Free Breakfast', 'Extra Person'];
break; //end Paradise Inn
case 'TetrisHotel':
strHotelName = 'Tetris Hotel';
strHotelDesc = 'Hotel Description Tetris Hotel';
strHotelPrice = ['980.00', '1,300.00', '1,600.00', '1,500.00', '1,800.00', '300.00', '150.00', '200.00'];
strHotelRoomType = ['Single Room', 'Delux Room','Twin Room', 'Matrimonial Room', 'Presidential Suites', 'Extra Bed', 'Free Breakfast', 'Extra Person'];
break; //end Tetris Hotel
case 'JamstoneInn':
strHotelName = 'Jamstone Inn';
strHotelDesc = 'Hotel Description Jamstone Inn';
strHotelPrice = ['980.00', '1,300.00', '1,600.00', '1,500.00', '1,800.00', '300.00', '150.00', '200.00'];
strHotelRoomType = ['Single Room', 'Delux Room','Twin Room', 'Matrimonial Room', 'Presidential Suites', 'Extra Bed', 'Free Breakfast', 'Extra Person'];
break; //end Jamstone Inn
}
return {
name: strHotelName,
desc: strHotelDesc,
price: strHotelPrice,
roomType: strHotelRoomType
}
};
刚刚注意到，除了酒店名称和描述之外，您每次都返回相同的值(您可能只是作为示例这样做，我不确定).您可以在声明时为所有变量分配其值(或将值分配为返回对象的属性)，而不是酒店名称和描述，您可以从参数 HotelName.类似的东西
Just noticed that you're also returning the same values other than the hotel name and description each time (you might have done this just as an example, I'm not sure). You could just assign all variables their value on declaration (or assign the values as properties of the returned object), other than the hotel name and description, which you could assign from the value of the argument for parameter HotelName. Something like
function hotelQuery(hotelName) {
return {
name: hotelName,
desc: 'Hotel Desciption' + hotelName,
// Keep prices as numbers and have a function to display them
// in the culture specific way. Numbers for prices will be easier to deal with
price: [980, 1300, 1600, 1500, 1800, 300, 150, 200],
roomType: ['Single Room', 'Delux Room','Twin Room', 'Matrimonial Room', 'Presidential Suites', 'Extra Bed', 'Free Breakfast', 'Extra Person']
}
}
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