在数字序列中查找第一个缺失的数字

2022-01-17 00:00:00 numbers sequence javascript

我试图弄清楚如何找到这样的数字序列中的第一个丢失的数字 (1,2,3,5,6,9,10,15)

I am trying to figure out how to find the first missing number of a sequence of numbers like this (1,2,3,5,6,9,10,15)

我想将第一个缺失的数字 #4 放入一个变量中以供以后使用，但不知道该怎么做?

I want to put the first missing number, #4, into an variable for later use but don't know how to do so?

我已经尝试过了，但这只给了我最后一个数字:

I have tried this but this only gives me the last number:

var mynumbers=new Array(1,2,3,6,9,10);
for(var i = 1; i < 32; i++) {
    if(mynumbers[i] - mynumbers[i-1] != 1) {
        alert("First missing number id: "+mynumbers[i]);
        break;
    }
}

首先，它会在数字序列中的洞"之后给我第一个数字，其次，如果我不插入中断，它会继续提醒所有在洞"之后出现的数字.我只想要从 1 到 32 的数字序列的第一个缺失数字.我该怎么做?

First of all it gives me the first number after an "hole" in the numbersequence, secondly it continues to alert all numbers comming after an "hole" if I don't insert an break. I only want the first missing number of an numbersequence from 1 - 32. How do i do so?

希望得到帮助并提前感谢 ;-)

Hoping for help and thanks in advance ;-)

推荐答案

这个怎么样

var mynumbers = new Array(1,2,3,6,9,10);
var missing;

for(var i=1;i<=32;i++)
{    
   if(mynumbers[i-1] != i){
        missing = i;
        alert(missing);
        break;
   }
}

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