在矩形中旋转点
我在一个矩形中有一个点，我需要旋转任意角度并找到该点的 x y.我如何使用 javascript 来做到这一点.
I have a point in a rectangle that I need to rotate an arbitrary degree and find the x y of the point. How can I do this using javascript.
在 x,y 下方会是 1,3，在我将 90 传递给方法后，它将返回 3,1.
Below the x,y would be something like 1,3 and after I pass 90 into the method it will return 3,1.
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基本上我正在寻找这种方法的勇气
Basically I am looking for the guts to this method
function Rotate(pointX,pointY,rectWidth,rectHeight,angle){
/*magic*/
return {newX:x,newY:y};
}
推荐答案
应该这样做:
function Rotate(pointX, pointY, rectWidth, rectHeight, angle) {
// convert angle to radians
angle = angle * Math.PI / 180.0
// calculate center of rectangle
var centerX = rectWidth / 2.0;
var centerY = rectHeight / 2.0;
// get coordinates relative to center
var dx = pointX - centerX;
var dy = pointY - centerY;
// calculate angle and distance
var a = Math.atan2(dy, dx);
var dist = Math.sqrt(dx * dx + dy * dy);
// calculate new angle
var a2 = a + angle;
// calculate new coordinates
var dx2 = Math.cos(a2) * dist;
var dy2 = Math.sin(a2) * dist;
// return coordinates relative to top left corner
return { newX: dx2 + centerX, newY: dy2 + centerY };
}
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