在jQuery中获取元素-moz-transform:旋转值
我有一个图层的 CSS 样式:
I have CSS style for a layer:
.element {
-webkit-transform: rotate(7.5deg);
-moz-transform: rotate(7.5deg);
-ms-transform: rotate(7.5deg);
-o-transform: rotate(7.5deg);
transform: rotate(7.5deg);
}
有没有办法通过 jQuery 获取当前的旋转值?
Is there a way to get curent rotation value through jQuery?
我试过了
$('.element').css("-moz-transform")
结果是 matrix(0.991445, 0.130526, -0.130526, 0.991445, 0px, 0px)
这并没有告诉我很多.我想要的是 7.5
.
The result is matrix(0.991445, 0.130526, -0.130526, 0.991445, 0px, 0px)
which doesn't tell me a lot. What I'm looking to get is 7.5
.
推荐答案
这是我使用 jQuery 的解决方案.
Here's my solution using jQuery.
这会返回一个数值,对应于应用于任何 HTML 元素的旋转.
This returns a numerical value corresponding to the rotation applied to any HTML element.
function getRotationDegrees(obj) {
var matrix = obj.css("-webkit-transform") ||
obj.css("-moz-transform") ||
obj.css("-ms-transform") ||
obj.css("-o-transform") ||
obj.css("transform");
if(matrix !== 'none') {
var values = matrix.split('(')[1].split(')')[0].split(',');
var a = values[0];
var b = values[1];
var angle = Math.round(Math.atan2(b, a) * (180/Math.PI));
} else { var angle = 0; }
return (angle < 0) ? angle + 360 : angle;
}
angle1 = getRotationDegrees($('#myDiv'));
angle2 = getRotationDegrees($('.mySpan a:last-child'));
等等……
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