xmlhttprequest 状态 302 的问题
我正在尝试获取链接 megaupload 中的真实路径，但总是这样，但这不起作用.
I am trying to get real path in link megaupload but always but this dont work.
function getRealURL(){
var st = new String("");
var req = new XMLHttpRequest();
req.open("GET","http://www.megaupload.com/?d=6CKP1MVJ",true);
req.send(null);
req.send(null);
req.onreadystatechange = function (aEvt) {
if (req.readyState == 4) {
if(req.status == 302){
//SUCESSO
st = req.responseText;
}
}
};//funcao
element.getElementById("id").setAttribute("value", st);
}
我需要这个链接:
Redirect to: http://www534.megaupload.com/files/c2c36829bc392692525f5b7b3d9d81dd/Coldplay - Warning Sign.mp3
插入这个:
http://www.megaupload.com/?d=6CKP1MVJ
推荐答案
XMLHttpRequest 默认自动跟随重定向，因此您看不到 302 响应.您需要将 nsIHttpChannel.redirectionLimit 属性设置为零以防止它:
XMLHttpRequest follows the redirect automatically by default so you don't see the 302 response. You need to set nsIHttpChannel.redirectionLimit property to zero to prevent it:
req.open("GET","http://www.megaupload.com/?d=6CKP1MVJ",true);
req.channel.QueryInterface(Components.interfaces.nsIHttpChannel).redirectionLimit = 0;
req.send(null);
并不是说您在此处使用的链接会重定向到任何地方，但这是一般方法.顺便说一句，您应该查看 req.getResponseHeader("Location")，而不是查看重定向的响应文本.
Not that the link you use here redirects anywhere but this is the general approach. Btw, instead of looking at the response text for redirects you should look at req.getResponseHeader("Location").
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