鼠标移动非常快时未正确捕获 Javascript 鼠标事件

Please let me know how to solve this. Also let me know if anything else is needed.

这里是代码

4 => qq[
    <ul id="primary">
        <li id="firstTab" onmouseover="changeSecondaryMenu('index','explore');" onmouseout="changeSecondaryMenu('explore');"><a></a></li>
        <li id="secondTab" onmouseover="changeSecondaryMenu('home','explore');" onmouseout="changeSecondaryMenu('explore');"><a></a></li>
        <li id="thirdTab" onmouseover="changeSecondaryMenu('requests','explore');" onmouseout="changeSecondaryMenu('explore');"><a></a></li>
        <li onmouseover="changeSecondaryMenu('explore','explore');"><a class="current" href="contact.pl">About Site</a></li>
    </ul>
],
);

my $primary_menu = $primary_menu{$primary_index};

my %secondary_menu = (
    1 => qq[
        <ul id="secondary" onmouseover="cancelTimeOut();" onmouseout="resetTab(event);">
            <li> <a>Summary</a> </li>
            <li> <a>Updates</a>  </li>
            <li> <a>History</a> </li>
            <li> <a>News/Stats</a> </li>
            <li> <a>Gratitude & Good Life</a> </li>
        </ul>
    ],

JavaScript

function cancelTimeOut(){
    clearTimeout(timer);
}

function resetTab(evt){
    var evt = evt || window.event; // event object
    var target = evt.target || window.event.srcElement; // event target
    var targetID = target.getAttribute("id");
    if (targetID == "secondary") {
        clearTimeout(timer);
        if(currentTab !=null){
            document.getElementById("secondary").innerHTML = tabs[currentTab];
            Rounded("ul#secondary","tr","#FFFFFF","transparent","smooth");
        }
    }
}

function changeSecondaryMenu(tab,selectedTab) {
    currentTab = selectedTab;
    clearTimeout(timer);
    document.getElementById("secondary").innerHTML = tabs[tab];
    Rounded("ul#secondary","tr","#FFFFFF","transparent","smooth");
}

推荐答案

视情况而定.Javascript 不会尝试在帧"之间进行插值.意思是，是的，如果您移动鼠标的速度足够快，一个 mousemove 事件将在对象的一侧触发，而下一个 mousemove 事件将在另一侧触发，因此 mouseover 和 out 永远不会被触发，您也不会更聪明.