如何取消绑定特定的事件处理程序

2022-01-15 00:00:00 events event-handling jquery javascript unbind

代码: 

$('#Inputfield').keyup(function(e)
        {
            if(e.which == 13)
            {
                functionXyz();
            }
            else
            {
                functionZyx();
            }
    });  


$(document).keyup(function(exit) {
              if (exit.keyCode == 27) { functionZzy(); }
});

问题:如何去掉keyCode == 27的keyup事件处理器，保持其他$(document).keyup事件处理器不变?

Question: How to remove the keyup event handler of keyCode == 27 and keep the other $(document).keyup event handlers intact?

推荐答案

您必须使用命名函数，以便在调用 .unbind()，像这样:

You have to use a named function so you can reference that specific handler when calling .unbind(), like this:

function keyUpFunc(e) {
  if (e.keyCode == 27) { functionZzy(); }
}
$(document).keyup(keyUpFunc);

然后在解除绑定时:

$(document).unbind("keyup", keyUpFunc);

相关文章