如何在 jQuery 属性选择器中将逻辑 OR 与逻辑 AND 结合起来?

2022-01-13 00:00:00 attributes jquery javascript jquery-selectors

给定以下 XML:

<users>
    <user state="CA" sex="m">Max</user>
    <user state="AZ" sex="f">Jen</user>
    <user state="OR" sex="f">Kim</user>
    <user state="NV" sex="m">Bob</user>
    <user state="CA" sex="m">Jon</user>
    <user state="AZ" sex="m">Jim</user>
    <user state="OR" sex="f">Joy</user>
    <user state="NV" sex="f">Amy</user>
</users>

使用 jQuery，有没有办法选择男性用户，来自 CA 或 NV，但不使用过滤功能?说清楚，我知道

Using jQuery, is there a way to select users who are male and are either from CA or NV, but without using the filter function? To be clear, I know that

$(xml).find("user[sex='m']")

只选择男性用户，而

$(xml).find("user[state='CA'],[state='NV']")

从 CA 或 NV 中选择所有用户.但我无法在单个选择器中将它们与逻辑 AND 结合起来.

selects all users from either CA or NV. But I am not able to combine both of them with a logical AND within a single selector.

但是，使用过滤器功能，以下工作:

Using the filter function, however, the following works:

$(xml).find("user").filter(function() {
    return $(this).attr('sex') == 'm' && ($(this).attr('state') == 'CA' || $(this).attr('state') == 'NV')
}).each(function() {
    alert($(this).text());
});

谢谢！

推荐答案

试试这个:

$(xml).find("user[sex='m'][state='CA'], user[sex='m'][state='NV']")

基本上，您将 sex 和 state 属性链接在一个简单的选择器中(这将是您的逻辑与)，并在每个状态重复一次(这将是你的逻辑或).

Basically you chain the sex and state attributes together in a single simple selector (this would be your logical AND), and repeat them once per state (and this would be your logical OR).

测试:

$(xml).find("user[sex='m'][state='CA'], user[sex='m'][state='NV']")
      .each(function() {
          alert($(this).text() + " - " + $(this).attr('state'));
      });

输出:

Max - CA
Bob - NV
Jon - CA

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