卡在按值/子键删除父推送键

2022-01-13 00:00:00 firebase javascript firebase-realtime-database ionic2 angularfire

我想按值/子键删除父按键:

I want to delete a parent pushed key by value/childkey:

export class FaqsPage {
  qS: Observable<any[]>;
  ques = '';
  ans = '';

constructor(private db: AngularFireDatabase) {}
ionViewDidLoad() { this.qS = this.db.list('table/faq').valueChanges(); }

removeItem(id){this.db.list('table/faq').remove(id);}

removeItem() 删除所有按键.难怪，因为我无法获得父密钥

removeItem() deleting the whole all pushed keys. No wonder because i couldn't get the parent key

//faq.html
<ion-list>
    <ion-item-sliding *ngFor="let el of qS | async">
      <ion-item>
        <b>{{ el.Q }}</b><br>{{ el.A }}
      </ion-item>
      <ion-item-options side="right">
        <button ion-button color="red" icon-only (click)="removeItem(el.key)"><ion-icon name="trash"></ion-icon></button>
      </ion-item-options>
    </ion-item-sliding>
  </ion-list>

由于 valueChanges()

el.key doesn't get the the key (e.g. Kzwv8d_i-0QZuf2NT8Z) because of valueChanges() and i have no idea how to do it within current iteration.

推荐答案

希望你用的是angularfire2

I hope you are using angularfire2

this.qS = this.db.list('table/faq').snapshotChanges().map(changes => {
  return changes.map(c => ({ key: c.payload.key, ...c.payload.val() }));
});

这将返回带有键的 qS

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