检查一个多边形点是否在传单中的另一个内部
我从传单 geoJSON 地图中选择了两组多边形坐标.父子坐标是坐标是:
I'm having two sets of polygon coordinates selected from leaflet geoJSON map. The parent and child coordinates are coordinates are:
var parentCoordinates=[
[
32.05898221582174,
-28.31004731142091
],
[
32.05898221582174,
-28.308044824292978
],
[
32.06134255975485,
-28.308044824292978
],
[
32.06134255975485,
-28.31004731142091
],
[
32.05898221582174,
-28.31004731142091
]
]
var childCoordinates=[
[
32.059904895722866,
-28.30970726909422
],
[
32.059904895722866,
-28.308743809931784
],
[
32.06089194864035,
-28.308743809931784
],
[
32.06089194864035,
-28.30970726909422
],
[
32.059904895722866,
-28.30970726909422
]
]
child在父区域内绘制如图:
The child is drawn inside the parent area as shown in the picture:
使用 Ray Casting 算法 来确定是否点位于多边形内,我无法确定,因为我得到的结果是错误的.请让我知道我做错了什么或任何其他方式来确定解决方案.谢谢
Using Ray Casting algorithm to determine if the point lies inside polygon I 'm not able to determine as the result I'm getting is false. Please let me know where I'm doing wrong or any other way to determine the solution.Thanks
推荐答案
我尝试了你的算法和另一个在这里找到的 https://rosettacode.org/wiki/Ray-casting_algorithm 并且都返回正确的值.
I tried with your algorithm and another found here https://rosettacode.org/wiki/Ray-casting_algorithm and both return the right value.
也许这个小提琴可以帮助你实现:
Maybe this fiddle can help you in the implementation :
https://jsfiddle.net/4psL2hoo/1/
您的算法
// Data
var parentCoordinates=[
[
32.05898221582174,
-28.31004731142091
],
[
32.05898221582174,
-28.308044824292978
],
[
32.06134255975485,
-28.308044824292978
],
[
32.06134255975485,
-28.31004731142091
],
[
32.05898221582174,
-28.31004731142091
]
]
var childCoordinates=[
[
32.059904895722866,
-28.30970726909422
],
[
32.059904895722866,
-28.308743809931784
],
[
32.06089194864035,
-28.308743809931784
],
[
32.06089194864035,
-28.30970726909422
],
[
32.059904895722866,
-28.30970726909422
]
]
// Other algo
function test(point, vs) {
// ray-casting algorithm based on
// http://www.ecse.rpi.edu/Homepages/wrf/Research/Short_Notes/pnpoly.html
var x = point[0], y = point[1];
var inside = false;
for (var i = 0, j = vs.length - 1; i < vs.length; j = i++) {
var xi = vs[i][0], yi = vs[i][1];
var xj = vs[j][0], yj = vs[j][1];
var intersect = ((yi > y) != (yj > y))
&& (x < (xj - xi) * (y - yi) / (yj - yi) + xi);
if (intersect) inside = !inside;
}
return inside;
};
for (var i = 0; i < childCoordinates.length; i++) {
var testPoint = childCoordinates[i];
console.log(JSON.stringify(testPoint) + ' in parentCoordinate ' + test(testPoint, parentCoordinates));
}
Rosetta 代码算法
//https://rosettacode.org/wiki/Ray-casting_algorithm
function contains(bounds, lat, lng) {
//https://rosettacode.org/wiki/Ray-casting_algorithm
var count = 0;
for (var b = 0; b < bounds.length; b++) {
var vertex1 = bounds[b];
var vertex2 = bounds[(b + 1) % bounds.length];
if (west(vertex1, vertex2, lng, lat))
++count;
}
return count % 2;
/**
* @return {boolean} true if (x,y) is west of the line segment connecting A and B
*/
function west(A, B, x, y) {
if (A.y <= B.y) {
if (y <= A.y || y > B.y ||
x >= A.x && x >= B.x) {
return false;
} else if (x < A.x && x < B.x) {
return true;
} else {
return (y - A.y) / (x - A.x) > (B.y - A.y) / (B.x - A.x);
}
} else {
return west(B, A, x, y);
}
}
}
var square = {name: 'square', bounds: [{x: 32.05898221582174, y: -28.31004731142091}, {x: 32.05898221582174, y: -28.308044824292978}, {x: 32.06134255975485, y: -28.308044824292978}, {x: 32.06134255975485, y: -28.31004731142091}]};
var shapes = [square];
var testPoints = [{lng: 32.059904895722866, lat: -28.30970726909422}, {lng: 32.059904895722866, lat: -28.308743809931784}, {lng: 32.06089194864035, lat: -28.308743809931784},
{lng: 32.06089194864035, lat: -28.30970726909422}];
for (var s = 0; s < shapes.length; s++) {
var shape = shapes[s];
for (var tp = 0; tp < testPoints.length; tp++) {
var testPoint = testPoints[tp];
console.log(JSON.stringify(testPoint) + ' in ' + shape.name + ' ' + contains(shape.bounds, testPoint.lat, testPoint.lng));
}
}
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