传单:更新 GeoJson 过滤器?

2022-01-12 00:00:00 geojson leaflet javascript

我想用数据填充 GeoJson 层，然后动态过滤要显示的特征.

I would like to populate a GeoJson layer with data and then dynamically filter what features to show.

我已经让过滤器功能工作，但我不知道如何更改过滤器然后刷新图层.

I have gotten the filter function to work but I do not know how to change the filter and then refresh the layer.

添加数据后有什么方法可以更新过滤器?

Is there any way I can update the filter after I have added the data?

推荐答案

我通过将每个功能类型添加到不同的 LayerGroup 基于特征的属性.例如

I did this by adding each feature type to a different LayerGroup based on a property of the feature. e.g.

GeoJSON

var data =[
  {
   type: "Feature",
   properties: {
      type: "type1"
   },
   geometry: {
      type: "Point",
      coordinates: [-1.252,52.107]
   }
  },
  {
   type: "Feature",
   properties: {
      type: "type2"
   },
   geometry: {
      type: "Point",
      coordinates: [-2.252,54.107]
   }
  }
];

创建 GeoJSON 层

//array to store layers for each feature type
var mapLayerGroups = [];

//draw GEOJSON - don't add the GEOJSON layer to the map here
L.geoJson(data, {onEachFeature: onEachFeature})//.addTo(map);

/*
 *for all features create a layerGroup for each feature type and add the feature to the    layerGroup
*/
function onEachFeature(feature, featureLayer) {

    //does layerGroup already exist? if not create it and add to map
    var lg = mapLayerGroups[feature.properties.type];

    if (lg === undefined) {
        lg = new L.layerGroup();
        //add the layer to the map
        lg.addTo(map);
        //store layer
        mapLayerGroups[feature.properties.type] = lg;
    }

    //add the feature to the layer
    lg.addLayer(featureLayer);      
}

然后您可以调用 Leaflet map.addLayer/removeLayer 函数，例如

Then you can call the Leaflet map.addLayer/removeLayer functions e.g.

//Show layerGroup with feature of "type1"
showLayer("type1");

/*
* show/hide layerGroup   
*/
function showLayer(id) {
    var lg = mapLayerGroups[id];
    map.addLayer(lg);   
}
function hideLayer(id) {
    var lg = mapLayerGroups[id];
    map.removeLayer(lg);   
}

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