使用 gulp-nodemon & 时无法使用 Ctrl+C 停止 Gulpgulp.watch 一起看

2022-01-12 00:00:00 javascript gulp

当我在没有 node 任务的情况下运行 gulp 时，它可以正常工作并按预期处理客户端文件，如果我运行 gulp node 它会按预期处理服务器文件.但是，如果我同时运行 gulp 它会按预期同时处理客户端和服务器文件，但是，它不会让我通过按Ctrl + C"退出(在 Windows 10 和 Mac El Capitan 上尝试过)).我在这里做错了吗?

When I run gulp without the node task, it works fine and processes client file as expected, If I run gulp node it processes server file as expected. However if I run both gulp it processes both client and server file as expected, however, it won't let me quit by pressing 'Ctrl + C' (Tried it on windows 10 & Mac El Capitan). Is there something I'm doing wrong here?

'use strict';
  var gulp = require('gulp');
    var connect = require('gulp-connect'); 
    var browserify = require('browserify'); 
    var source = require('vinyl-source-stream'); 
    var nodemon = require('gulp-nodemon');

    var config = {
        port: 9005,
        devBaseUrl: 'http://localhost',
        paths: {
            html: './src/*.html',
            dist: './dist',
            js: './src/**/*.js',
            images: './src/images/*',
            mainJs: './src/main.js',
            css: [
                'node_modules/bootstrap/dist/css/bootstrap.min.css',
                'node_modules/bootstrap/dist/css/bootstrap-theme.min.css'
            ]
        }
    };

gulp.task('connect', function () {
    connect.server({
        root: ['dist'],
        port: config.port,
        base: config.devBaseUrl,
        livereload: true
    });
});


gulp.task('html', function () {
    gulp.src(config.paths.html)
        .pipe(gulp.dest(config.paths.dist))
});

gulp.task('js', function () {
    browserify(config.paths.mainJs)
        .bundle()
        .on('error', console.error.bind(console))
        .pipe(source('bundle.js'))
        .pipe(gulp.dest(config.paths.dist + '/scripts'))
        .pipe(connect.reload())

});

gulp.task('node', function () {
    nodemon({
        script: 'server/index.js',
        ext: 'js',
        env: {
            PORT: 8000
        },
        ignore: ['node_modules/**','src/**','dist/**']
    })
    .on('restart', function () {
        console.log('Restarting node server...');
    })
});

gulp.task('watch', function () {
    gulp.watch(config.paths.js, ['js']);
});

gulp.task('default', ['html', 'js', 'connect', 'node', 'watch']);

推荐答案

我之前遇到过类似的问题，这就是您要找的:

I had a similar issue before this is what you're looking for :

process.on('SIGINT', function() {
  setTimeout(function() {
    gutil.log(gutil.colors.red('Successfully closed ' + process.pid));
    process.exit(1);
  }, 500);
});

只需将此代码添加到您的 gulp 文件中即可.它将监视 ctrl + C 并正确终止该过程.如果需要，您也可以在超时中添加一些其他代码.

Just add this code to your gulp file. It will watch the ctrl + C and properly terminate the process. You can put some other code in the timeout also if desired.

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