如何 Gulp-Watch 多个文件?
我有这样的事情:
gulp.task('default', ['css', 'browser-sync'] , function() {
gulp.watch(['sass/**/*.scss', 'layouts/*.css'], function() {
gulp.run('css');
});
});
但它不起作用，因为它会监视两个目录，即 sass 和 layouts 目录以进行更改.
but it does not work, because it watches two directories, the sass and the layouts directory for changes.
如何让它工作，以便 gulp 监视这些目录中发生的任何事情?
How do I make it work, so that gulp watches anything that happens inside those directories?
推荐答案
gulp.task('default', ['css', 'browser-sync'] , function() {
gulp.watch(['sass/**/*.scss', 'layouts/**/*.css'], ['css']);
});
sass/**/*.scss 和 layouts/**/*.css 将监视每个目录和子目录对 .scss<的任何更改/code> 和 .css 文件更改.如果您想将其更改为 any 文件，请在最后一位 *.*
sass/**/*.scss and layouts/**/*.css will watch every directory and subdirectory for any changes to .scssand .css files that change. If you want to change that to any file make the last bit *.*
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