如何编写带有回调的 jQuery 函数?

2022-01-11 00:00:00 jquery jquery-plugins javascript

我有以下功能:

function loadProjects(pID) {

    $.ajax({
        url: myURL,
        success: function (dataJS) {XXXXXXXXXXXXXXXX}
    });
}

我像这样调用这个函数 loadProjects(1);

I call this function like so loadProjects(1);

问题是我希望能够在成功后定义一个回调函数，并且我想在我做 loadProjects(1, callback:{whatever js is included here gets call back after success})的时候包含它

Issue is I want to be able to define a callBack function after success, and I'd like to include it when I do loadProjects(1, callback:{whatever js is included here gets called back after success})

如何让函数接受回调?如何将回调传递给该函数?

How can I have a function accept a callback? How can I pass a callback to that function?

谢谢

推荐答案

function loadProjects(pID, callbackFunction)
{
    $.ajax({
        url: myURL,
        success: function (dataJS)
        {
            if(typeof callbackFunction == 'function')
            {
                callbackFunction.call(this, dataJS);
            }
        }
    });
}

用法:

loadProjects(pID, function(dataJS)
{
    // do stuff with your dataJS, bear in mind you can call the parameter any name.
});

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