在我所有的执行正确之前调用 gapi.client.load(...) 吗?

2022-01-10 00:00:00 google-drive-api javascript

我不确定我是否理解正确，是否需要创建这样的函数:

I'm not sure if I'm understanding this correctly, do I need to create a function like this:

function execute(callback) {
    gapi.client.load('drive', 'v2', function() {
      callback();
    });
}

然后对于我所有的电话都这样称呼它?

And then for all my calls call it like this? 

function retrieveAllFiles() {
    execute(function(){
      var request = gapi.client.drive.files.list();
      request.execute(function(resp) { 
          console.log(resp);
      }
    }
}

function deletefile() {
    execute(function(){ 
    ...

效果很好，但我不确定这是否是正确的做法?

It works fine but I'm not sure if this is the correct way of doing it?

推荐答案

是的，这可能是最简单的方法.这当然是一种可以接受的方式.

Yes, that is probably the easiest way to do it. It is certainly an acceptable way.

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