Discord js/检查用户是否在特定的语音频道中
我希望我的机器人通过使用<afk [radio]"在 2 个 afk 频道中的 1 个中移动用户.命令.但我首先想检查用户是否已经在 AFK 频道中.我试过了:
I want my bot to move a user in 1 of 2 afk channels by using a "<afk [radio]" command. But i first want to check if the user is allready in an AFK Channel. I tried:
const voiceChannel = message.member.voice.channel;
const voiceChannelID = message.member.voice.channelID;
if (!voiceChannel) {
return message.channel.send('You are not in an voice Channel so why move to AFK?');
} else if (voiceChannelID === '789186504483536937', '791444742042943548') {
return message.channel.send('You are already in an AFK channel!');
} else if (!args.length) {
return member.voice.setChannel('789186504483536937');
}
但是当我尝试使用<afk"时命令机器人发送消息:
But when i try t use the "<afk" command the bot send the message:
您已经在 AFK 频道中！
You are already in an AFK channel!
任何想法为什么这样做?
Any ideas why it does this?
推荐答案
问题是
if (voiceChannelID === '789186504483536937', '791444742042943548')
这不是多个条件的工作方式.用 or 操作符分隔.
This is not how multiple conditionals work. Seperate it with the or operator.
if (voiceChannelID === '789186504483536937' || voiceChannelID === '791444742042943548')
您可以将您尝试做的事情想象为传入两个不同的条件 f(x, y).Javascript 中的 if 语句将只检查最后一个 (y) 和791444742042943548".是真实的，因为它是非空的.
You can think of what you were trying to do as passing in two different conditions, f(x, y). If statements in Javascript will only check for the last one (y), and "791444742042943548" is truthy since it is non-null.
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