在给定的不和谐频道中搜索满足条件的所有消息并删除
我正在尝试编写一个代码,该代码将检查频道中的所有消息以查找包含某些单词的消息,如果确实包含这些单词,则将其删除.所以像:
I was trying to make a code that will check all messages in a channel for messages that contain certain words, and delete them if it does contain them. So something like:
if(msg.content.startsWith(prefix+'clean') {
let check = msg.content.split(prefix+'clean')[1]; // Condition, in this case if it containts a certain string
msg.channel.fetchMessages().then(msgs => { // Get messages to check
let msglog = msgs.array() // Make an array with all the messages fetched
for(var i = 0; i < msglog.size; i++) { // Loop to check all messages in array
if (check in msglog[i]) {
// Code to delete that message
};
};
});
};
我知道这不会检查整个频道,它只会检查最后 50 条消息,但我不知道如何让它检查整个频道,所以在我找到方法之前会这样做.
I am aware that this will not check the entire channel and it will only check the last 50 messages, but I do not know how to make it check the whole channel so this will do until I find out how to do that.
但是什么代码会删除通过检查的消息?或者我可以用什么不同的方法来解决这个问题?
But what code would delete the message that passes the check? Or any different way I could approach this?
我好像还不够清楚,假设一个频道有以下对话:
It seems I was not clear enough, so let's say a channel has the following conversation:
A:伙计们!
B 人:嗨
C 人:再见
假设我想通过我的机器人删除所有带有Hi"的消息,我应该怎么做?注意:我不会在消息发送后立即删除它,我只想在我想删除它时删除它.
Let's say I want to delete all the messages with "Hi" in it through my bot, how should I do this? Note: I do not with to delete a message right after it has been sent, I only want to delete it when I want to do so.
推荐答案
bulkDelete 功能删除给定的新消息超过两周.
The bulkDelete function delete given messages that are newer than two weeks.
if(msg.content.startsWith(prefix+'clean') {
let check = msg.content.split(prefix+'clean')[1]; // Condition, in this case if it containts a certain string
msg.channel.fetchMessages().then(msgs => { // Get messages to check
let msgDel = msgs.filter(msgss => msgss.content.includes(check)) // Finds all messages with 'check'
msg.channel.bulkDelete(msgDel) // Deletes all messages that got found
});
};
要删除超过 2 周的消息,您必须手动遍历消息以删除它们:
To delete the messages older than 2 weeks, you have to iterate through the messages manually to delete them:
async function deleteReturnLast(chan, option, prevMsg, cond) {
return chan.fetchMessages(option)
.then(async msgs => {
if (msgs.size === 0){
if (cond(prevMsg)) {
prevMsg.delete()
.then(d => console.log('last message deleted: ' + d.content))
.catch(err => console.log('ERR>>', err, prevMsg.content, option.before)); }
return prevMsg;
};
let last = msgs.last();
for (const[id, msg] of msgs) {
let tmp = (id === last.id) ? prevMsg : msg;
if (cond(tmp)) {
tmp.delete()
.then(d => console.log('Message deleted: ' + d.content))
.catch(err => console.log('ERR>>', err));
}
};
return last;
})
.catch(err => console.log('ERR>>', err));
}
function cond(msg) {
return !msg.content.includes('a');
}
client.on('message', async function(msg) {
let chan = msg.channel;
let last = chan.lastMessage;
while (last !== (last = await deleteReturnLast(chan, {limit: 2, before: last.id}, last, cond))){
};
});
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