CSS nth-child 应用奇偶规则，但每 4 项切换一次

2022-01-10 00:00:00 css-selectors css

我有一个 divs 列表，它与一个类连续出现 4 个，我想创建一个棋盘背景样式，意思是:

I have a list of divs that appear 4 in a row with a class and I would like to create a checkerboard background style, meaning:

  • 为奇数和偶数 div
    • 应用不同的背景颜色
  • 将每行的奇偶切换为奇偶

我试过了

.boxwrapper:nth-child(2n-1), .boxwrapper:nth-child(2n) {
    background:#ff0000;
}
.boxwrapper:nth-child(4n-2), .boxwrapper:nth-child(4n-3) {
    background:#0000ff;
}

它适用于奇偶 div，但不能让它每 4 个项目切换一次.我正在为 4n-1、4n+1 的事情头疼，如果我能做到这一点，瞧！

and it works fine for odd-even divs but cant get it to switch every 4 items. I'm headaching over the 4n-1, 4n+1 stuff, if I could get that right voila!

结果应该是这样的:

推荐答案

Demo

http://jsfiddle.net/mykhA/1/

<div class="container">
    <div class="box"></div><div class="box"></div><div class="box"></div><div class="box"></div>
    <div class="box"></div><div class="box"></div><div class="box"></div><div class="box"></div>
    <div class="box"></div><div class="box"></div><div class="box"></div><div class="box"></div>
    <div class="box"></div><div class="box"></div><div class="box"></div><div class="box"></div>
</div>​

CSS

.container {
    width: 100px;
    height: 100px;
}

.line {
    width: 100px;
    height: 25px;
}

.box {
    width: 25px;
    height: 25px;
    float: left;
}

.box:nth-child(8n+2) {
    background-color: red;
}

.box:nth-child(8n+4) {
    background-color: red;
}
.box:nth-child(8n+5) {
    background-color: red;
}

.box:nth-child(8n+7) {
    background-color: red;
}

.box:nth-child(8n+1) {
    background-color: blue;
}

.box:nth-child(8n+3) {
    background-color: blue;
}

.box:nth-child(8n+6) {
    background-color: blue;
}

.box:nth-child(8n) {
    background-color: blue;
}
​

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