如何在一个表中存储多个选项?

The following should get you going with a good start as you tinker. Joins too.

create table student
(   studentId int auto_increment primary key,
    fullName varchar(100) not null
    -- etc
);

create table dept
(   deptId int auto_increment primary key,
    deptName varchar(100) not null -- Economics
    -- etc
);

create table course
(   courseId int auto_increment primary key,
    deptId int not null,
    courseName varchar(100) not null,
    -- etc
    CONSTRAINT fk_crs_dept FOREIGN KEY (deptId) REFERENCES dept(deptId)
);

create table SCJunction
(   -- Student/Course Junction table (a.k.a Student is taking the course)
    -- also holds the attendance and grade
    id int auto_increment primary key,
    studentId int not null,
    courseId int not null,
    term int not null, -- term (I am using 100 in below examples for this term)
    attendance int not null, -- whatever you want, 100=always there, 0=he must have been partying,
    grade int not null, -- just an idea   
    -- See (Note Composite Index) at bottom concerning next two lines.
    unique key(studentId,courseId,term), -- no duplicates allowed for the combo (note student can re-take it next term)
    key (courseId,studentId),
    CONSTRAINT fk_sc_student FOREIGN KEY (studentId) REFERENCES student(studentId),
    CONSTRAINT fk_sc_courses FOREIGN KEY (courseId) REFERENCES course(courseId)
);

创建测试数据

insert student(fullName) values ('Henry Carthage'),('Kim Billings'),('Shy Guy'); -- id's 1,2,3
insert student(fullName) values ('Shy Guy');

insert dept(deptName) values ('History'),('Math'),('English'); -- id's 1,2,3

insert course(deptId,courseName) values (1,'Early Roman Empire'),(1,'Italian Nation States'); -- id's 1 and 2 (History dept)
insert course(deptId,courseName) values (2,'Calculus 1'),(2,'Linear Algebra A'); -- id's 3 and 4 (Math dept)
insert course(deptId,courseName) values (3,'World of Chaucer'); -- id 5 (English dept)

-- show why FK constraints are important based on data at the moment
insert course(deptId,courseName) values (66,'Fly Fishing 101'); -- will generate error 1452. That dept 66 does not exist
-- That error is a good error to have. Better than faulty data

-- Have Kim (studentId=2) enrolled in a few courses
insert SCJunction(studentId,courseId,term,attendance,grade) values (2,1,100,-1,-1); -- Early Roman Empire, term 100 (made up), unknown attendance/grade
insert SCJunction(studentId,courseId,term,attendance,grade) values (2,4,100,-1,-1); -- Linear Algebra A
insert SCJunction(studentId,courseId,term,attendance,grade) values (2,5,100,-1,-1); -- World of Chaucer

-- Have Shy Guy (studentId=3) enrolled in one course only. He is shy
insert SCJunction(studentId,courseId,term,attendance,grade) values (3,5,100,-1,-1); -- Early Roman Empire, term 100 (made up), unknow attendance/grade
-- note if you run that line again, the Error 1062 Duplicate entry happens. Can't take same course more than once per term

一些简单的问题.

全部显示，使用表格别名(缩写)来减少打字次数，提高可读性(有时)

select c.courseId,c.courseName,d.deptId,d.deptName
from course c
join dept d
on c.deptId=d.deptId
order by d.deptName,c.courseName -- note the order
+----------+-----------------------+--------+----------+
| courseId | courseName            | deptId | deptName |
+----------+-----------------------+--------+----------+
|        5 | World of Chaucer      |      3 | English  |
|        1 | Early Roman Empire    |      1 | History  |
|        2 | Italian Nation States |      1 | History  |
|        3 | Calculus 1            |      2 | Math     |
|        4 | Linear Algebra A      |      2 | Math     |
+----------+-----------------------+--------+----------+

select s.StudentId,s.FullName
from SCJunction j
join student s
on j.studentId=s.studentId
where j.courseId=5 and j.term=100
+-----------+--------------+
| StudentId | FullName     |
+-----------+--------------+
|         2 | Kim Billings |
|         3 | Shy Guy      |
+-----------+--------------+

select s.StudentId,s.FullName,c.courseId,c.courseName
from SCJunction j
join student s
on j.studentId=s.studentId
join course c
on j.courseId=c.courseId
where s.studentId=2 and j.term=100
order by c.courseId DESC -- descending, just for the fun of it
+-----------+--------------+----------+--------------------+
| StudentId | FullName     | courseId | courseName         |
+-----------+--------------+----------+--------------------+
|         2 | Kim Billings |        5 | World of Chaucer   |
|         2 | Kim Billings |        4 | Linear Algebra A   |
|         2 | Kim Billings |        1 | Early Roman Empire |
+-----------+--------------+----------+--------------------+

delete from SCJunction
where studentId=2 and courseId=4 and term=100

+-----------+--------------+----------+--------------------+
| StudentId | FullName     | courseId | courseName         |
+-----------+--------------+----------+--------------------+
|         2 | Kim Billings |        5 | World of Chaucer   |
|         2 | Kim Billings |        1 | Early Roman Empire |
+-----------+--------------+----------+--------------------+